(Y+5)+(2y+4y^2-2)=

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Solution for (Y+5)+(2y+4y^2-2)= equation:


Simplifying
(Y + 5) + (2y + 4y2 + -2) = 0

Reorder the terms:
(5 + Y) + (2y + 4y2 + -2) = 0

Remove parenthesis around (5 + Y)
5 + Y + (2y + 4y2 + -2) = 0

Reorder the terms:
5 + Y + (-2 + 2y + 4y2) = 0

Remove parenthesis around (-2 + 2y + 4y2)
5 + Y + -2 + 2y + 4y2 = 0

Reorder the terms:
5 + -2 + Y + 2y + 4y2 = 0

Combine like terms: 5 + -2 = 3
3 + Y + 2y + 4y2 = 0

Solving
3 + Y + 2y + 4y2 = 0

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + Y + 2y + -3 + 4y2 = 0 + -3

Reorder the terms:
3 + -3 + Y + 2y + 4y2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + Y + 2y + 4y2 = 0 + -3
Y + 2y + 4y2 = 0 + -3

Combine like terms: 0 + -3 = -3
Y + 2y + 4y2 = -3

Add '-2y' to each side of the equation.
Y + 2y + -2y + 4y2 = -3 + -2y

Combine like terms: 2y + -2y = 0
Y + 0 + 4y2 = -3 + -2y
Y + 4y2 = -3 + -2y

Add '-4y2' to each side of the equation.
Y + 4y2 + -4y2 = -3 + -2y + -4y2

Combine like terms: 4y2 + -4y2 = 0
Y + 0 = -3 + -2y + -4y2
Y = -3 + -2y + -4y2

Simplifying
Y = -3 + -2y + -4y2

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